History, asked by Sagar123r567wobdo, 1 year ago

Find the temperature at which volume and pressure of 28gm nitrogen gas become 10dm3 and 2.46 atmosphere respectively ​

Answers

Answered by nottyboy84
4

A)

W = 28g

P = 2.46 atm

V = 10 litres

m = 28

∴PV=wmRT (R = 0.0821 litre atm/K/mol)

T=mPVw×R

T=28×2.46×1028×0.0821

=688.82.2988

= 299.64 K

Hence answer is (b)

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