Question

find the temperature of mixture is 50 grams of water at 70 degree centigrade mixed with 70 grams of water at 50 degree centigrade​

Answer 1

we know that, in caloriemetry

heat gain by water= heat lost by water

(at 50*C) (at 70*C)

$70(t - 50) = 50(70 - t) \\ 7t - 350 = 350 - 5t \\ 12t = 700 \\ t = {58.33 }^{\degree}c$

therefore, temperature of the final mixture is 58.33*C