Find the tenth and thirteenth term of the series 4,8,16??
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Answer:
T10=512
Explanation:
the geometric sequence given is:
1,2,4,8 ...
When provided with a geometric sequence we must first calculate the common ratio r
r is obtained by dividing a term by its preceding term:
1) 21=2
2) 42=2
for this sequence the common ratio r=2 the first term a=1
The 10th term can be obtained through formula:
Tn=arn−1=1×2(10−1) , where n = 10
T10=1×29
T10=1×512=512
T10=512
Explanation:
the geometric sequence given is:
1,2,4,8 ...
When provided with a geometric sequence we must first calculate the common ratio r
r is obtained by dividing a term by its preceding term:
1) 21=2
2) 42=2
for this sequence the common ratio r=2 the first term a=1
The 10th term can be obtained through formula:
Tn=arn−1=1×2(10−1) , where n = 10
T10=1×29
T10=1×512=512
simimallik1:
Nd the thirteenth? ?
i have done it
Bt i was not understand
its easy
a13=a+12d
and just put the values of a and d
Ok i will try thanks
ok
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0
hope this helps you.......
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