Question

Find the tenth term AP (√8,√18, √32)​

Answer 1

Answer:

a=√8 a=2√2

d=√18-√8 = 3√2 - 2√2 =√2

so the Ap continues as

2√2,3√2,4√2,5√2.

so the fourth term is 5√2 =√50

Step-by-step explanation:

a=√8 a=2√2

d=√18-√8 = 3√2 - 2√2 =√2

so the Ap continues as

2√2,3√2,4√2,5√2.

so the fourth term is 5√2 =√50

Answer 2

Answer

The 10th term of the given AP is 10√2 or √200

$\bf \large \underline{Given : }$

The AP is

• √8 , √18 , √32

$\bf \large \underline{To \: Find : }$

• The 10th term of the AP

$\bf \large \underline{Solution : }$

Given , the AP is

➝ √8 , √18 , √32

➝ 2√2 , 3√2 , 4√2

Therefore ,

first term , a = 2√2

and common difference,

» d = 3√2 - 2√2

» d = √2

We know that ,

$\longrightarrow \: \: \rm a _{n} = a + (n - 1)d \\ \\ \implies \rm a_{10} = 2 \sqrt{2} + (10 - 1) \sqrt{2} \\ \\ \rm \implies a_{10} = 2\sqrt{2} + 9 \sqrt{2} \\ \\ \rm\implies a_{10} = 10 \sqrt{2}$

Therefore, the 10th term of the AP is 10√2 or √200