find the tenth term of sequence root2, root8, roo18
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2
the tenth term will be 10√2=√200 (Answer)
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Answered by
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term = √2
comman difference = 2√2 - √2 = √2
hence
tenth term a10 = a + (n-1)d
= √2 + (10-1) × √2
= √2(10
= 10✓2
comman difference = 2√2 - √2 = √2
hence
tenth term a10 = a + (n-1)d
= √2 + (10-1) × √2
= √2(10
= 10✓2
thnx
it is very easy so no thanx
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