find the term ap is 8,11,14,17,....., is 758
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6
here a=8
d=11-8=3
an=758
n=??
an=a+(n-1)d
758=8+(n-1)×3
758-8=(n-1)3
750÷3=n-1
250=n-1
n=250+1
n=251
d=11-8=3
an=758
n=??
an=a+(n-1)d
758=8+(n-1)×3
758-8=(n-1)3
750÷3=n-1
250=n-1
n=250+1
n=251
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