Question

find the term factors of 9p²q² - 4pq²
2. 15x²- 13x + 2​

Answer 1

Step-by-step explanation:

((0 - (3•5x2)) - 13x) - 2 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

-15x2 - 13x - 2 = -1 • (15x2 + 13x + 2)

Trying to factor by splitting the middle term

3.2 Factoring 15x2 + 13x + 2

The first term is, 15x2 its coefficient is 15 .

The middle term is, +13x its coefficient is 13 .

The last term, "the constant", is +2

Step-1 : Multiply the coefficient of the first term by the constant 15 • 2 = 30

Step-2 : Find two factors of 30 whose sum equals the coefficient of the middle term, which is 13 .

-30 + -1 = -31

-15 + -2 = -17

-10 + -3 = -13

-6 + -5 = -11

-5 + -6 = -11

-3 + -10 = -13

-2 + -15 = -17

-1 + -30 = -31

1 + 30 = 31

2 + 15 = 17

3 + 10 = 13 That's it

Answer 2

Answer:

Step-by-step explanation:

Ans 1)

9p²q²-4pq²

=pq²(9p - 4)

Ans 2)

15x² - 13x + 2

=15x²-10x-3x +2

5x(3x-2)-1(3x-2)

=(5x-1)(3x-2)

Hope this helps.