find the term independent of x in the binomial expansion of (2x-1/x)^10
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term independent of x index of the means index of the term should be zero.
first we will find the general term.
Tr+1= 10Cr(2x)^10-r(-1/x)^r
solve this and you will get index of x=10-2r
put 10-2r=0
r=5
if r=5then term will be 6th
put r=5 in the general term
and you will get T6= -4032
first we will find the general term.
Tr+1= 10Cr(2x)^10-r(-1/x)^r
solve this and you will get index of x=10-2r
put 10-2r=0
r=5
if r=5then term will be 6th
put r=5 in the general term
and you will get T6= -4032
harry71:
its noy right answer
I'm solving it. by mistake I submitted the answer
hmmm
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