find the term independent of x, xnot equel to 0,in the expansion of [3/2 x²- 1/ 3x ]⁶
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General term in the expansion of [3/2x2-1/3x]6. Thus, the term will be independent of x, if the index is zero, i.e., 12 − 3r = 0 ⇒ r = 4 Hence, 5th term is independent of x and is given by Read more on Sarthaks.com - https://www.sarthaks.com/222098/find-the-term-independent-of-x-in-the-expansion-of-3-2x-2-1-3x-6
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