Question

Find the term nature of roots of equation 13√3x^2+10x+√3=0.

Answer 1

Answer:

Step-by-step explanation:

a= 13 root3, b= 10, c= root 3

bsq - 4ac = ( 10)sq -  4( 13 root3 ) (root3)

=100-156

= -56

As D<0

so it has no real roots