Find the term nature of roots of equation 13√3x^2+10x+√3=0.
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Answer:
Step-by-step explanation:
a= 13 root3, b= 10, c= root 3
bsq - 4ac = ( 10)sq - 4( 13 root3 ) (root3)
=100-156
= -56
As D<0
so it has no real roots
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