find the term of an ap is 6 and its common difference is 5 find its 11 term
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Answered by
2
Answer:
It is given that the first term of an A.P is a=6 and the common difference is d=5.
Let us find the following terms:
a+d=6+5=11
a+2d=6+(2×5)=6+10=16
a+3d=6+(3×5)=6+15=21
We know that the general form of an arithmetic progression with first term a and common difference d is a,a+d,a+2d,......
General term=a
n
=a+(n−1)d
Hence, the required A.P is 6,11,16,21,......
Answered by
0
Answer:
56
Step-by-step explanation:
To find a term, the formula is a + (n - 1)d, where a means the first term, n means the serial no. of the term we have to find and d means the common difference between 2 terms.
So, in this question
a₁₁ = a + (n - 1)d
a₁₁ = 6 + (11 - 1)5 = 56
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