Find the term of an ap is 9,12,15,18 ........which is 39 more than its 36th term
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Answered by
8
hi friend,
given 9,12,15,18 ........ is in AP where a =9
d=3
then its 36th term is a+(n-1)d
→9+(35)3
→9+105
→114
given, the term which is 39 more than 36th term
→114+39
→153
now , an=a+(n-1)d
153=9+(n-1)3
144/3=n-1
48=n-1
n=49
so 49th term is 39 more than 36th term..
I hope this will help u :)
given 9,12,15,18 ........ is in AP where a =9
d=3
then its 36th term is a+(n-1)d
→9+(35)3
→9+105
→114
given, the term which is 39 more than 36th term
→114+39
→153
now , an=a+(n-1)d
153=9+(n-1)3
144/3=n-1
48=n-1
n=49
so 49th term is 39 more than 36th term..
I hope this will help u :)
Answered by
3
♠Answer♠
SupermanINFINITY : “nth term of an AP :
An = a + (n-1)d
36th term = 9 + (35)3 = 114
now , 114+39= 153
then ,
153 = 9+(n-1)3
n = 147/3 = 49 ."
#SupermanINFINITY
SupermanINFINITY : “nth term of an AP :
An = a + (n-1)d
36th term = 9 + (35)3 = 114
now , 114+39= 153
then ,
153 = 9+(n-1)3
n = 147/3 = 49 ."
#SupermanINFINITY
SupermanINFINITY:
best of kucj
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