Math, asked by ninav7779, 1 year ago

Find the term of an ap is 9,12,15, ........which is 36 more than its 36th term

Answers

Answered by ilhamameen2004
4

Answer:


Step-by-step explanation:

Solution :-


Given A.P. = 9, 12, 15, 18...........


a = 9

d = 12 - 9 

d = 3


Now, according to question.

a₃₆ = a + (n - 1)d

a₃₆ = 9 + (36 - 1)3

= 9 + 35*3

= 9 + 105

a₃₆ = 114


The required term is 39 more than its 36th term.

So,

⇒ a₃₆ + 39 

⇒ 114 + 39 = 153


an = 153

153 = a + (n - 1)d

153 = 9 + (n - 1)3

153 = 9 + 3n - 3

3n = 153 + 3 - 9

3n = 147

n = 147/3

n = 49


So, the required term is 49th term of the given A.P.




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