Question

Find the term of sequences whose nth terms are: i. an=n(n+1)(2n+1)/6 ; a10 ii. an=10n+5/n2 ; a11​

Answer 1

Answer:

an = n(n+1)(2n+1) / 6

a10 = 10(10+1)(2(10)+1) / 6

= 10(11)(21) / 6

= 2310 / 6

= 385

an = (10n+5) / n²

a11 = (10(11)+5) / 11²

= (110+5) / 121

= 115 / 121