Find the term of term sequence-3,1,5,9...
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Solution
We know the sum of n terms of an A.P with first term a and the common difference d is:
S
n
=
2
n
[2a+(n−1)d]
Here, it is given that the first term is a=−3, common difference is d=1−(−3)=1+3=4 and n=17, therefore, the sum is:
S
n
=
2
17
[(2×−3)+(17−1)4]=
2
17
[−6+(16×4)]=
2
17
(−6+64)=
2
17×58
=17×29=493
Hence, the sum is 493
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