Find the term of the arithmetic progression 9,12,15,18,...which is 39 more than its 36th term.
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49th term of the AP will be 39 more than the 36th term.
Step-by-step explanation:
Given: arithmetic progression 9,12,15,18,...
Find: the term that is 39 more than its 36th term.
Solution:
a = 9
d = 3
an = a +(n-1)d
ax - a36 = 39
a + (x-1)3 - a -35d = 39
(x-1)3 - 35(3) = 39
(x-1)3 = 39 + 105
x-1 = 144/3
x = 48 + 1
= 49
49th term of the AP will be 39 more than the 36th term.
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