Question

find the term T18of an A.P 7,13,,19,25....

Answer 1

a= 7
d= 13-7 = 6

t18 = a+(n-1) d

= 7+(18-1) 6

= 7+102

= 109

Answer 2

Hii There!!!

In the given A.P ;

a = 7 , d = a2-a1 = 13 - 7 = 6 , n = 18
& t18 = an = ?

Since we know that,

$\bf{an=a+(n-1)d}$

So, on putting values we get ;

a18 = 7 + ( 18 - 1 ) × 6

=> 7 + 17 × 6

=> 7 + 102

=> 109

Therefore, $\boxed{t18=109}$

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Hope it helps ☺️