Find the terminal velocity of a rain drop of radius 0.01mm. Coefficient of viscosity of air is 1.8*10^-5 N-s/m^2 and the density is 1.2 kg/m^3. Density of water= 1000 kg/m^3 .
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hey mate
here's the solution
here's the solution
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afrinbano773:
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Answered by
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Hello friend,
◆ Answer-
v = 0.0123 m/s
◆ Explaination-
# Given-
r = 0.01 mm = 10^-5 m
ρ = 1000 kg/m^3
ρ0 = 1.2 kg/m^3
η = 1.8×10^-5 Ns/m^2
# Solution -
Terminal velocity of the rain drop is given by -
v = 2(ρ–ρ0)gr^2 / 9η
v = 2(1000-1.2)×10×(10^-5)^2 / (9 × 1.8×10^-5)
v = 0.0123 m/s
Terminal velocity of the raindrop is 0.0123 m/s.
Hope this helps you...
◆ Answer-
v = 0.0123 m/s
◆ Explaination-
# Given-
r = 0.01 mm = 10^-5 m
ρ = 1000 kg/m^3
ρ0 = 1.2 kg/m^3
η = 1.8×10^-5 Ns/m^2
# Solution -
Terminal velocity of the rain drop is given by -
v = 2(ρ–ρ0)gr^2 / 9η
v = 2(1000-1.2)×10×(10^-5)^2 / (9 × 1.8×10^-5)
v = 0.0123 m/s
Terminal velocity of the raindrop is 0.0123 m/s.
Hope this helps you...
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