Question

find the
the area
of the
BC=8 cm
triangle
AB= 5cm
AC = 5 cm​

Answer 1

Answer:

Here, using heron's formula,

Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is

$\sqrt{s(s-a)(s-b)(s-c)},$

where s is the semi-perimeter of the triangle; that is,

$s=\frac{a+b+c}{2}.$

Here, a=8, b=5, c=5.

s=$\frac{8+5+5}{2}$

s=9cm.

$A = \sqrt{9(9-8)(9-5)(9-5)},$

$A = \sqrt{9(1)(4)(4)},$

$A = \sqrt{3*3*4*4},$.................9 can be written as 3×3.

$A = \sqrt{3^{2}*4^{2} },$..............square and square root gets cancelled

$A = 3*4$

$A = 12cm^{2}$

HOPE IT HELPS :D

Answer 2

Answer:

Your answer is in attachment