Question

Find the the cost of covering the floor of a room 9 metre by 6 metre with tiles each tile measuring 25 cm and 30 cm @ rupees 200 per tile

Answer 1

Answer:

1560 rupees

Step-by-step explanation:

room measuring = 54 metre square

1 metre = 100 cm

54 metre square = 54×100 = 5400 cm square

tiles measuring = 25 cm×30 cm = 750 cm square

$\frac{5400}{750} = \frac{39}{5} = \frac{39}{5} \times 200 = 1560 \:rupees$

Answer 2

The cost of covering the floor is Rs. 144000

Step-by-step explanation:

length of the room = 9 m

breadth of the room = 6 m

area of the room = l× b

= 9×6  = 54 m²

length of the tile = 25 cm = 0.25 m

breadth of the tile = 30 cm = 0.30 m

area of the one tile =  l× b = 0.25×0.30 = 0.075 m²

number of tiles required to cover the floor = $\frac{area of room}{area of 1 tile}$

= $\frac{54}{0.075}$

= 720 tiles

now, cost of 1 tile = Rs. 200

cost of 720 tiles = 200 × 720= Rs. 144000

hence ,

The cost of covering the floor is Rs. 144000

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