Find the the enclosed by the given figure
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fewage4406:
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SolutioN :-
In above fig. firstly we have to find height ( HF ) of triangle.
In ∆ FGH
→ GH² + HF² = GF²
→ 5² + HF² = 13²
→ HF² = 169 - 25
→ HF = √144
→ HF = 12 cm
Area of ∆FGH = 1/2 × b × h
→ 1/2 × 5 × 12
→ 5 × 6
→ 30 cm²
There are 2 ∆ so multiply it by 2
→ 2 × 30
→ 60 cm²
Area of rectangle ABEF = L × B
→ 20 × 17
→ 340 cm²
Area of figure = Area of rectangle + Area of triangle
Area of figure = 340 + 60
Area of figure = 400 cm²
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