find the the list number which when divided by 6 15 and 18 leaves remainder 5 in each case
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Answer:
6 = 3*2
15 = 3*5
18 = 2*3*3
therefore, L.C.M. (6,15,18) = 2 * 3² * 5
L.C.M. (6,15,18) = 90
90+5 = 95
therefore, 95 is the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.
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