Question

find the
the Pesimeter
Rectangle
of
L-16
B=9
.​

Answer 1

Answer:

Perimeter = 2×(L+B)

so,2×(16+9)

2×25

so, perimeter=50

Answer 2

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Given,

• L = 16
• B = 9

To find :

• Perimeter of rectangle

We know that,

⇒Perimeter of rectangle = 2 ( l + b )

⇒2 (16+9)

⇒2 (25)

⇒50

∴ Perimeter of rectangle = 50