Question

find the the value of domain and range of the real function f(x)= x^3-8/x^2-1​

Answer 1

Step-by-step explanation:

For domain x²-1≠0 ,

Or x≠±1

So,the domain of function is R -{-1,1 }

For range y = f(x) = x³-8/x²-1 = (x-2)(x²+4x+4)/(x-1)(x+1)

As domain is not defined for {-1,1}

also we know the range is the set of images of f(x) in this case this the set of all the vlues of f(x) excluding f(-1) & f(1)