Question

find the the value of k , k^2 ×3 -k ×9.​

Answer 1

Answer:

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${k}^{2} \times 3 - k \times 9$

$= k {}^{2} \times 3 - k \times 9$

$= 3k {}^{2} - k \times 9$

$= 9k - k \times 9$

$k = \frac{9}{9} = 1$

Therefore k=1