Question

Find the
the zero of the polynomial
49x² - 64
​

Answer 1

Answer:

$49 {x}^{2} - 64 \\ \\ = {(7x)}^{2} - {(8)}^{2} \\ \\ = (7x + 8)(7x - 8) \\ \\ formula \: used \: \\ \\ {a}^{2} - {b}^{2} \\ \\ = (a + b)(a - b) \\ \\ so \: zero \: of \: the \: polynomial \: are \\ \\either \: 7 x + 8 = 0 \\ \\ = > 7x = - 8 \\ \\ = > x = \frac{ - 8}{7} \\ \\ or \: 7x - 8 = 0 \\ \\ = > 7x = 8 \\ \\ = > x = \frac{8}{7}$

hope this much helps uh ❣️

Answer 2

Refer to the above attachment for your answer.

hope it's helpful : )