Question

Find the the zeroes of polynomials a)px=4*3 c b)q(y),=3y-1​

Answer 1

Answer:

a)

Given, p(x)=x

2

−4x+3

=x

2

−3x−x+3

=x(x−3)−1(x−3)

=(x−3)(x−1)

For zeroes of polynomial, p(x)=0

i.e. (x−3)(x−1)=0

or, x=3 or x=1

Let, α=3 and β=1

α+β=

a

−b

αβ=

a

c

Here, a=1b=−4c=3

α+β=4

αβ=3

b)

The graph of −3y+x−12=0 intersect the x-axis at (12,0).

Hence the zero of −3y+x−12=0 is (12,0) as it intersects at x-axis at (12,0).