Question

Find the third side of a triangle when the perimeter is (6+2a+4a^2 ) units and two sides are (2a+3a^2 ) units and (3+2a-a^2 ) units.

Answer 1

Step-by-step explanation:

perimeter= sum of all sides/3

6+2a+4a^2 = 2a+3a^2 + 3+2a-a^2+ x/3

18+6a+12a^2= 4a+2a^2+3+x

x= 15+2a+10a^2