Find the third side of a triangle whose perimeter is (7x^22+7x-7)and the two sides are (5x+56)and (6x^2+3x-1)
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Step-by-step explanation:
perimeter = sum of all sides
7x² + 7x - 7 = (5x+56)+(6x²+3x-1) + Third side
Third side = (7x²+7x-7) - (6x²+8x+55)
= x² - x - 62
Answered by
0
Answer:
62
Step-by-step explanation:
perimeter = sum of all sides
7x² + 7x - 7 = (5x+56)+(6x²+3x-1) + Third side
Third side = (7x²+7x-7) - (6x²+8x+55)
= x² - x - 62
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