Find the third side of a triangle whose two sides are (2x? 3y + 4) and (5x? 6) and the perimeter is (-x² + 5y -10).
Answers
Answered by
0
Answer:
Themediapromotes_____inpubliclife.
Step-by-step explanation:
Themediapromotes_____inpubliclife.
Answered by
2
Answer:
Given equation are
2x
2
−5xy+2y
2
=0
2x
2
−(4+1)xy+2y
2
=0
2x
2
−4xy−xy+2y
2
=0
2x
2
(x−2y)−y(x−2y)=0
(x−2y)(2x−y)=0
If x−2y=0, x=2y . (1)
2x−y=0 , y=
2
x
y=2x
let x=a
y=2x=2a
Point A(a, 2a)
If y=b
x=2y
x=2b
Point B(2b, b)
Centroid =(1,1) Given that and from (1)
Point 0 (0,0)
So, Centroid formula,
3
a+2b+0
=1 ,
3
2a+b+0=1
On solving
a=1, b=1
so, point A(1,2)
B(2,1)
From point A and B to.
y−2=
2−1
1−2
(x−1)
y−2=(−1) (x−1)
y−2=−x+1
x+y−3=0
Hence, this is the answer
Similar questions