Math, asked by blink2092, 1 month ago

Find the third side of a triangle whose two sides are (2x? 3y + 4) and (5x? 6) and the perimeter is (-x² + 5y -10).​

Answers

Answered by harithuviha
0

Answer:

Themediapromotes_____inpubliclife.

Step-by-step explanation:

Themediapromotes_____inpubliclife.

Answered by мααɴѕí
2

Answer:

Given equation are

2x

2

−5xy+2y

2

=0

2x

2

−(4+1)xy+2y

2

=0

2x

2

−4xy−xy+2y

2

=0

2x

2

(x−2y)−y(x−2y)=0

(x−2y)(2x−y)=0

If x−2y=0, x=2y . (1)

2x−y=0 , y=

2

x

y=2x

let x=a

y=2x=2a

Point A(a, 2a)

If y=b

x=2y

x=2b

Point B(2b, b)

Centroid =(1,1) Given that and from (1)

Point 0 (0,0)

So, Centroid formula,

3

a+2b+0

=1 ,

3

2a+b+0=1

On solving

a=1, b=1

so, point A(1,2)

B(2,1)

From point A and B to.

y−2=

2−1

1−2

(x−1)

y−2=(−1) (x−1)

y−2=−x+1

x+y−3=0

Hence, this is the answer

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