Question

find the third side of traingle ABC where B. is at 90° . (hint:) solve it by Pythagoras theorem.
1. AB=42cm , AC= 50cm, BC=?
2. BC=27,AC=30,AB=?

Answer 1

BC^2+AB^2=AC^2_____________________________ BC^2=AC^2-AB^2____________________________- BC^2=50^2-42^2_____________________ BC^2=736 BC=√736 BC=4×√46=27.13____________________ Similarly for the given data AB=3√19=13.08=√171

Answer 2

BC×BC=AC×AC-BA×BA 
 BC×BC=50×50-42×42.
 BC×BC=2500-1764
Bc×BC=736
bc=√737
SIMILARLY
                 AB=3√19