Question

Find the third term of an A.P. whose first term is 6 and common difference is -3. *
3
0
9
-9

Answer 1

Answer:

a = 6

d = -3

a3 = a + 2d

= 6 + 2×-3

= 6-6

= 0

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Answer 2

Given :

first term of A.P. =a =t1 =6

common difference(d) = -3

To find :

third term of A.P

Solution :

$we\:know\\t_{n}=a+(n-1)d\\t_{3}=6+(3-1)(-3)\\t_{3}=6-6=0\\t_{3}=0$

The thrid term of given A.P. is 0