Question

Find the third vertex of a triangle, if two of
its vertices are at (-3, 1) and (0, -2) and
the centroid is at the origin. Help me out....​

Answer 1

Answer:

(3,1) is the centroid

Step-by-step explanation:

x3=3 , y3=1

Answer 2

Answer:

given: P (-3, 1 ), Q (0, -2) Centroid C (0, 0)

to find third vertex

Step-by-step explanation:

C x, y = [(x1+x2+x3) / 3 , (y1+y2+y3) / 3]

C x = 0 = (-3 + 0 + x3) /3

=> 0 = (-3 + x3) / 3

=> 0*3 = (- 3 + x3)

=> 0 = - 3 + x3

=> x3 = 3 [ by transposing - 3 ]

Cy = 0 = (1 - 2 + y3) / 3

=> 0 = (- 1 + y3) / 3

=> 0*3 = -1 + y3

=> 0 = - 1 + y3

=> y3 = 1 [ by transposing - 1 ]

therefore third vertex is R (3, 1)