Find the third vertex of the triangle ABC if two of its vertex are at A(-3,1) and B(0,2) and the midpoint of BC is at D(3/2,1/2)
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Let C (a,b)
D is the mid point of BC
We know that coordinates of mid point are given by
Coordinates of D [(0+a)/2 , (2+b)/2]
But D (3/2,1/2)
On comparing
a/2=3/2 => a=3
(2+b)/2=1/2 => b=-1
so coordinates of third vertex are (3,-1)
D is the mid point of BC
We know that coordinates of mid point are given by
Coordinates of D [(0+a)/2 , (2+b)/2]
But D (3/2,1/2)
On comparing
a/2=3/2 => a=3
(2+b)/2=1/2 => b=-1
so coordinates of third vertex are (3,-1)
Deepjyoti11:
Thank you for quick answer it helped me
welcome
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