find the three consective natural number such that five times the smallest number is 9 more than fours times the greatest number
Answers
Answer:
The three consecutive numbers are 17,18 and 19.
Step-by-step explanation:
Let x-1,x,x+1 be the three consecutive natural numbers.
Given that 5 times the smallest number is 9 more than 4 times the greatest number.
⇒5(x-1)=9+4(x+1)
⇒5x-5=9+4x+4
⇒5x-4x=9+4+5
⇒x=18
The middle number is 18
The smallest number is x-1=17
The greatest number is x+1=19
Verification:-
5(17)=85
4(19)+9=85
Answer:
The three numbers are 17, 18 and 19.
Step-by-step explanation:
Since, we need to find three consecutive numbers,
Let these numbers be n, n+1 and n+2 respectively.
According to the question,
5*n = 9 + 4* (n+2)
=> 5n = 9 + 4n + 8
=> 5n - 4n = 9 + 8
=> n = 17
As the first number is n, it is 17.
The second number is n+1 which is 17+1 = 18
The third number is n+2 = 17+2 = 19
Therefore, the three numbers are 17, 18 and 19.