Question

Find the three consecutive even number whose sum is 147

Answer 1

let the consecutive no. be x+x+1+x+2
x+x+1+x+2=147
3x+3=147
3x=145
x =145÷3
x=48
so consecutive no. are 48;49;50

Answer 2

A.T.Q.,
(x)+(x+2)+(x+4) = 147
3x+6 = 147
3x = 147-6
x = 141/3
x = 47
hence the required 3 consecutive 'ODD' numbers are 47,49,51.