Question

Find the three consecutive integers such that three times the lowest one plus five times the middle one is equal to nine times the largest one.​

Answer 1

Answer:

Suppose 3 consecutive integers are x, x+1, x+2

smallest is x, largest is x+2

3x= x+2 +18

2x= 20

x=10

Three consecutive integers are, 10, 11, 12

Check: smallest number=10

3 times smallest = 30 which is 18 more than largest number 12.