Find the three consecutive integers whose sum is 99
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Answer:
Given : consecutive integers so,
x ,x+1,x+2
Step-by-step explanation:
Let's solve
So, x+x+1+x+2=99
3x+3=99
3x=99-3
3x=96
x= 96/3
32 hence the first integer is 32
now
second integer: 32+1=33
third integer: 32+2=34
Now let's check: 32+33+34=99
hope it helped you..
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