Find the three consecutive natural numbers such that the sum of the first and second is 15 more than the third
Answers
Answered by
0
We can write the numbers as m-1, m and m+1
Then m-1+m=m+1+15
m=17
So the numbers are 16, 17 and 18
Then m-1+m=m+1+15
m=17
So the numbers are 16, 17 and 18
Answered by
3
Answer
Let numbers = x, x+1, x+2
x + x + 1 = x + 2 + 15
=> 2x = 17 + x - 1
=> x = 16
Numbers = 16, 17, 18
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