Find the three consecutive number such that the sum of the first and the second is 39 more than the third number
Answers
Answered by
2
the formula is -
smallest number is x
x+x+1=x+2+39
2x+1=x+41
2x-x=41-1
x=40
x+1=41
x+2=42
smallest number is x
x+x+1=x+2+39
2x+1=x+41
2x-x=41-1
x=40
x+1=41
x+2=42
Similar questions