find the three consecutive numbers such that the sum of twice is the greatest number and thrice the least number is 584
Answers
Answered by
24
let the consecutive numbers are x, x+1,x+2.
Atq. 2(x+2) + 3(x) = 584
= 2x+4 + 3x = 584
= 5x+4 = 584
= 5x = 584-4
= 5x = 580
= x = 580/5
= x = 116
therefore the numbers are x = 116
x+1 = 117
and x+2 = 118.
Atq. 2(x+2) + 3(x) = 584
= 2x+4 + 3x = 584
= 5x+4 = 584
= 5x = 584-4
= 5x = 580
= x = 580/5
= x = 116
therefore the numbers are x = 116
x+1 = 117
and x+2 = 118.
Answered by
10
Hello mate
Here is your answer,
Let the three consecutive numbers be x, x+1 and x+2 respectively.
2(x+2) + 3(x) = 584
2x + 4 + 3x = 584
5x = 580
x = 580/5
x = 116
x+1 = 117
x+2 = 118
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