Find the three consecutive numbers such that three times the middle number is greater than the sum of the other two by 11
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10, 11 and 12 are the required numbers
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let the nos be x,x+1,x+2
then 3(x+1)=x+x+2+11
3x+3=2x+13
x=13-3=10
therefore the numbers are 10,11,12
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then 3(x+1)=x+x+2+11
3x+3=2x+13
x=13-3=10
therefore the numbers are 10,11,12
HOPE IT HELPS!!^_^
PLEASE MARK MY ANSWER AS THE BRAINLIEST!!
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