Question

Find the three consecutive numbers whose sum is 396.​

Answer 1

let the number be x.
so, x+1,x+2
then,
x+ x+1+x+2=396
3x+3=396
3x=396-3
3x= 393
x=393/3
SO, x = 131
then x+1 = 131+1=132
x+2=131+2=133
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Answer 2

$\purple\star\mathfrak\green{\large{\underline{\underline{Solution:-}}}}$

$\red\star\mathfrak\purple{\large{\underline{\underline{Let\: the \: unknown\:number\:be\:x}}}}$

$\pink\star\mathfrak\blue{\large{\underline{\underline{Therefore\:Numbers\:are\:\bold\red{\:x+1,\:x+2\:x+3}}}}}$

$\purple\star\mathfrak\orange{\large{\underline{\underline{Now, \: according\: to\: Question}}}}$

$\bold \red{(x + 1) +( x + 2)(x + 3) =396 }$

$\bold \red{{\implies}3 x + 6 = 396}$

$\bold \red{{\implies3x = 396 - 6}}$

$\bold \red{{ \implies}3x = 390}$

$\bold \red{{\implies}x = \frac{390}{3} }$

$\bold \red{{ \implies}x} \mathfrak \green{ = 130}$

$\red\star\mathfrak\blue{\large{\underline{\underline{Therefore,\: numbers\:are:-}}}}$

$\mathfrak \blue{ \implies}\bold \red{x + 1} \mathfrak \pink{ = } \mathfrak \purple{130 + 1 \mathfrak \green= \pink \star131 \pink \star}$

$\mathfrak \blue{\implies} \bold \red{x + 2} \mathfrak \pink{ = } \mathfrak \purple{130 + 2 \mathfrak \green= \pink \star132 \pink \star}$

$\implies \bold \red{x + 3} \mathfrak \pink{ = } \mathfrak \purple{130 + 3 \mathfrak \green{=} \pink \star 133 \pink \star}$