find the three consecutive numbers whose sum is 45 and tgeir product is 3240
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let the three consecutive number be x, x + 1, x + 2
x +x + 1 +x+ 2 is equal to 45
3x+3=45
3x=42
x=14
Number are 14 15 and 16
x +x + 1 +x+ 2 is equal to 45
3x+3=45
3x=42
x=14
Number are 14 15 and 16
dattubhai:
wrong sum who says the difference is 1 the three consecutive terms should be x,x+d,x+2d
Answered by
0
let the numbers be x,x+1,x+2
then x+x+1+x+2=45
3x+3=45
3x=42
x=14
so the required nos are 14,15 and 16..
product of 14 ,15 and 16
=14×15×16=210×16=3360
for the product part kindly see the value given in the question once again
then x+x+1+x+2=45
3x+3=45
3x=42
x=14
so the required nos are 14,15 and 16..
product of 14 ,15 and 16
=14×15×16=210×16=3360
for the product part kindly see the value given in the question once again
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