find the three consecutive numbers whose sum is 69
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Answers
Answered by
28
The consecutive numbers would be;x,x+1,x+2
sum=69
Then,
x+x+1+x+2=69
3x+3=69
3X=66
X =66/3
X=22
Therefore,the three consecutive numbers are , 22,23,24.
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Answered by
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Solutions :-
Let the three consecutive number be x, x + 1 and x + 2 respectively.
Find the value of x :-
A/q
=> x + x + 1 + x + 2 = 69
=> 3x + 3 = 69
=> 3x = 69 - 3
=> 3x = 66
=> x = 66/3 = 22
Therefore,
First number = x = 22
Second number = 22 + 1 = 22 + 1 = 23
Third number = 22 + 2 = 22 + 2 = 24
Answer : The three consecutive numbers are 22, 23 and 24 respectively.
Let the three consecutive number be x, x + 1 and x + 2 respectively.
Find the value of x :-
A/q
=> x + x + 1 + x + 2 = 69
=> 3x + 3 = 69
=> 3x = 69 - 3
=> 3x = 66
=> x = 66/3 = 22
Therefore,
First number = x = 22
Second number = 22 + 1 = 22 + 1 = 23
Third number = 22 + 2 = 22 + 2 = 24
Answer : The three consecutive numbers are 22, 23 and 24 respectively.
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