find the three consecutive numbers whose sum is 96
Answers
Answered by
4
let the three consecutive numbers be x, x+1 and x +2
Now,
if their sum is 96,
then,
x+x+1+x+2 = 96
3x +3 = 96
3(x+1) = 96
x+1 = 96/3
x+1 = 32
x = 32-1
x = 31
then,
three consecutive numbers are :-
31
31+1 = 32
31+2 = 33
i hope this will help you
-by ABHAY
Now,
if their sum is 96,
then,
x+x+1+x+2 = 96
3x +3 = 96
3(x+1) = 96
x+1 = 96/3
x+1 = 32
x = 32-1
x = 31
then,
three consecutive numbers are :-
31
31+1 = 32
31+2 = 33
i hope this will help you
-by ABHAY
tawaseem:
Bro,but this question comes in the Arithmetic Progression chapter.Your answer is right but they won't give full marks if answered in your way.
plz don't mistake me but i just wanted to help you to know the common mistakes.
sorry if you took it in a wrong way.
no bro thanks to you , i am maths aryabhatta and it is very harmful for rank
so thanks
mention not bro
which class r u in?
sorry, i can't tell
ok
haha tawaseem
Answered by
3
Let the numbers be a-d , a and a+d.
a-d+a+a+d=96
3a = 96
a = 32.
d=1.(Since,the numbers are consecutive)
=>a-d = 32-1 = 31.
Similarly, a+d= 32+1 = 33
Thus,
the 3 numbers are 31 , 32 and 33.
a-d+a+a+d=96
3a = 96
a = 32.
d=1.(Since,the numbers are consecutive)
=>a-d = 32-1 = 31.
Similarly, a+d= 32+1 = 33
Thus,
the 3 numbers are 31 , 32 and 33.
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