Question

find the three consecutive odd integer such that the sum of the first number two less than the second number and three more than the third number is 70​

Answer 1

Answer:

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Step-by-step explanation:

Three consecutive odd integer so let's consider the following terms:

Let the first variable be x

let the second variable be x + 2

third variable ( x + 2) + 2 = x + 4

So sum of first less than second and three more than third so we will apply following methods

=> x + (x + 2 - 2 ) two less

=> + ( x + 4 + 3 ) three more than third

So bringing the equation together

=> x + ( x + 2 - 2 ) + ( x + 4 + 3) = 70

=> x + x + x + 4 + 3 = 70

=> 3x + 7 = 70

=> 3x = 63

=> x = 21

=> x = 21 first odd integer

=> x + 2 = 21 + 2 = 23 second odd integer

=> x + 4 = 21 + 4 = 25 third odd integer

Answer 2

Answer:

13

Step by Step explanations are given in the images above holding x as a common variable in this case.