Question

Find the three consecutive odd numbers whose sum 219

Answer 1

let the no. be a, a+1,a+2 then
3a+3=219
(a+1)3=219
a+1 =73
a=72
hence no. are=72,73,74

Answer 2

Answer:

The three consecutive natural numbers are 72, 73 and 74  

Step-by-step explanation:

Let the three consecutive natural numbers be x, x + 1 and x + 2  

Their sum is 219

According to the given condition

 

x + x + 1 + x + 2 = 219

 

→ 3x + 3 = 219

 

→ 3x = 219 - 3

 

→ 3x = 216

→ x =  

→ x = 72

∴ 1st natural number → x

→ 72

∴ nd natural number → x + 1

→ 72 + 1

→ 73

∴ 3rd natural number → x + 2

→ 72 + 2

→ 74