Question

find the three consecutive odd numbers whose sum is 987
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Answer 1

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$x + (x + 2) + (x + 4) = 987$

$3x + 6 = 987$

$3x = 987 - 6$

$3x = 981$

$x = 981/3$

$x = 327$

Other numbers :-

$(x + 2) = (327 + 2) = 329$

$(x + 4) = (327 + 4) = 331$

Therefore, the numbers are 327, 329 and 331.

Answer 2

(X) + (X + 1) + (X + 2) = 987

X + X + 1 + X + 2 = 987

3X + 3 = 987

3X = 984

X = 984/3

X = 328

Which means that the first number is 328, the second number is 328 + 1 and the third number is 328 + 2. Therefore, three consecutive integers that add up to 987 are 328, 329, and 330.

328 + 329 + 330 = 987

hope it helps..