Question

Find the three consecutive odd numbers whose sum is 987.​

Answer 1

Answer:

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Let the numbers be :

• x
• x + 2
• x + 4

⟶ x + (x + 2) + (x + 4) = 987

⟶ 3x + 6 = 987

⟶ 3x = 987 - 6

⟶ 3x = 981

⟶ x = 981/3

⟶ x = 327

Other numbers :

⟶ (x + 2) = (327 + 2) = 329

⟶ (x + 4) = (327 + 4) = 331

Therefore, the numbers are 327, 329 and 331.

Answer 2

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 987

3X + 3 = 987

3X + 3 - 3 = 987 - 3

3X = 984

3X/3 = 984/3

X = 328

Which means that the first number is 328, the second number is 328 + 1 and the third number is 328 + 2. Therefore, three consecutive integers that add up to 987 are 328, 329, and 330.

328 + 329 + 330 = 987

We know our answer is correct because 328 + 329 + 330 equals 987 as displayed above.